Question

In: Statistics and Probability

1. Data on ICU hospitalization (X) and number of death (Y) for 5 days due to...

1. Data on ICU hospitalization (X) and number of death (Y) for 5 days due to COVID-19 is given.

Date In ICU (X) Death (Y)
04/25 50 21
04/26 80 35
04/27 87 31
04/28 92 45
04/29 118 50
Total 427 182

Find estimate  βˆ1β^1

2. Data on ICU hospitalization (X) and number of death (Y) for 5 days due to COVID-19 is given.

Date In ICU (X) Death (Y)
04/25 50 21
04/26 80 35
04/27 87 31
04/28 92 45
04/29 118 50
Total 427 182

Find estimate  βˆ0β^0

3. Data on ICU hospitalization (X) and number of death (Y) for 5 days due to COVID-19 is given.

Date In ICU (X) Death (Y)
04/25 50 21
04/26 80 35
04/27 87 31
04/28 92 45
04/29 118 50
Total 427 182

Use the fitted regression model to estimate the number of death when number of patients in ICU is 500 rounded to closest number.

Solutions

Expert Solution

Solution:
Regression equation can be written as
Y = β^0 +β^1X
Here Y is the dependent variable
X is the independent variable
β^0 is the intercept of the regression line
β^1 is the slope of the regression line
The slope of the regression line can be calculated as
Slope = ((n*Xi*Yi) - (Xi * Yi))/((n*Xi^2) - (Xi)^2))

X Y X^2 Y^2 XY
50 21 2500 441 1050
80 35 6400 1225 2800
87 31 7569 961 2697
92 45 8464 2025 4140
118 50 13924 2500 5900
427 182 38857 7152 16587


Slope = ((5*16587) - (427*182))/((5*38857)-(427*427)) = 5221/11956 = 0.4367
Solution(b)
The intercept of the regression line can be calculated as
Intercept = (Yi - Slope*Xi)/n = (182 - 0.4367*182)/5 = -4.64/5 = -0.8929
Solution(c)
Regression equation can be written as
Y = -0.8929 + 0.4367*X
If X = 500
Than Y = -0.8929 + 0.4367*X = -0.8929 + 0.4367*500 = 217.45 or 218


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