Question

FILL IN THE BLANKS: At an alpha level of .01, test the null hypothesis against the alternative that the mean WEIGHT of this sample is no different from the average population weight (u = 152 (151.67 pounds). (5 points)

Step 1: Ho: = 152 pounds

Ha: (not equal to) 152 pounds

Step 2: Alpha level = 0.01

Step 3: Sampling distribution is ____________________

Step 4: Decision Rule — I will reject the Ho if the |_____| value falls at or beyond the |_____| of _____, otherwise I will fail to reject

Step 5: Calculation — t-test_obs__/ = ____

Step 6: Summary—Since the |____| of ____ falls at or beyond the |____| of ____, I therefore  _________________.

Step 7: Conclusion—Since _________________ Ho occurred, I conclude that  __________________________ in mean WEIGHT value.

Construct appropriate confidence interval for the WEIGHT problem.

Confidence interval for mean population weight:

            Sample mean = 152

t critical value – _____

SM =

u = M +/- t (SM)

u = _____

M = _____

99% confident that population weight mean (u) falls between __________ and __________

Answer 1

Step 1. Null hypothesis H0 : U= population mean weight = 152 pounds

Against the alternative Hypothesis Ha : U is not equal to 152 pounds ( two tailed alternative)

Step 2 = 0.01 level of significance

Step 3. sampling distributionis t distribution

Step 4 Decision rule Iwill reject the H0 if modulus of tcal value falls at or beyond the Modulus or +/- of t critical value otherwise i will fail to reject

Step 5 calculation of t test statistic = (sample mean - population mean) / S,E ( sample mean)

S tep 6 summary since calculated value of t falls or beyond the critical value of t therefore we accept or reject H0

or since the modulus of tcal value falls or beyond the modulus of t tab value therefore we accept or reject H0

Step 7.conclusion

Since Acceptance of H0 occured I conclude that 152 is the population mean weight

Construct appropriate confidence interval for the weight problem

Confidece interval for mean population weight

Sample mean = 152

t critical value table value of t for ( n-1) degrees of freedom at = 0.01 level of significance

where n= sample size

SM = standard error of sample mean

   U= M+/- t (SM)

U= population mean weight

M= sample mean weight

99% confident that population mean weight (U) falls between M- t (SM) and M+ t (SM)