Question

An object is 32cm in front of a convex mirror with a focal length of -19cm .Locate the image?

Is the image upright or inverted?

An object is 15cm in front of a concave mirror with a focal length of 22. Locate the image.cm.

Is the image upright or inverted?

Answer 1

a. Focal length, F
Distance of Object from mirror, Do
Distance of Image from mirror, Di
Magnification, M
Height of Object, Ho
Height of Image, Hi

The focal length is half of the radius of curvature and is negative since it is a convex mirror.
F = -19cm

Do = 32cm

The equation relating F, Do, and Di is
1/F = 1/Do + 1/Di
Solve for Di while plugging in the values for F and Do you get
Di = -11.92cm

Now for finding the height of the image we need the Magnification equation
M = -Di/Do = Hi/Ho
M = -(-11.92cm)/(32cm) = Hi/(Xcm) (x is always positive)
Solve for Hi
Hi = 0.3725*X cm (inverted)

b.

The focal length is half of the radius of curvature and is negative since it is a convex mirror.
F = 22cm

Do = 15cm

The equation relating F, Do, and Di is
1/F = 1/Do + 1/Di
Solve for Di while plugging in the values for F and Do you get
Di = -47.14cm

Now for finding the height of the image we need the Magnification equation
M = -Di/Do = Hi/Ho
M = -(-47.14cm)/(15cm) = Hi/(Xcm) (x is always positive)
Solve for Hi
Hi = 3.14*X cm (upright)