Question

Consider the following code:

import java.util.Scanner;

public class Main {

   public static void main(String[] args) {

   Scanner in = new Scanner(System.in);

String input = "";

System.out.println("Enter the first number: ");
  
input = in.nextLine();
int a = 0;
int b = 0;
  
a = Integer.parseInt(input);
  
System.out.println("Enter the second number: ");
input = in.nextLine();
  
b = Integer.parseInt(input);
  
int result = 0;

result = a/b;
  
System.out.println("a/b : " + result);

   }

Copy the code to your Main.java file and run it with the following inputs:
34 and 0;
‘Thirty-four’ as the first input.

What prevented the program from running successfully?

Update the code, so that it can handle cases a) and b).

Please note the following:
You have to use try-catch to handle exceptions.
To determine exception classes, that you need to catch, use error message from the respective case (a) and b)). Hint: to handle String-to-integer conversion, use NumberFormatException;
Exceptions should be caught so that:
Code never crashes due to non-numeric input (both for first and second values);
Code never crashes due to division by zero;
If non-numeric value is entered for a or b, program should output "Error: entered value is not an integer number. Exiting..." and exit (use System.exit(0); to exit);
If zero value is entered for b, program should output " Error: cannot divide by zero. Exiting..." and exit (use System.exit(0); to exit);
Hints: Use 3 try-catch blocks in total. Try block should only contain the command, that can throw an exception.

Answer 1

import java.util.Scanner;

public class Main {

        public static void main(String[] args) {

                Scanner in = new Scanner(System.in);

                String input = "";

                System.out.println("Enter the first number: ");

                input = in.nextLine();
                int a = 0;
                int b = 0;
        
                // First try catch block
                try {
                        a = Integer.parseInt(input);
                }catch(NumberFormatException ex) {
                        System.out.println("Error: entered value is not an integer number. Exiting...");
                        System.exit(0);
                }

                System.out.println("Enter the second number: ");
                input = in.nextLine();

                
                // Second try catch block
                try {
                        b = Integer.parseInt(input);
                }catch(NumberFormatException ex) {
                        System.out.println("Error: entered value is not an integer number. Exiting...");
                        System.exit(0);
                }
                
                int result = 0;
                
                //Third try catch block
                try {
                result = a / b;
                } catch(Exception e) {
                        System.out.print(" Error: cannot divide by zero. Exiting...");
                        System.exit(0);
                }

                System.out.println("a/b : " + result);

        }
}

OUTPUT: