A wheel of radius 0.280 m, which is moving initially at 33 m/s, rolls to a...

A wheel of radius 0.280 m, which is moving initially at 33 m/s, rolls to a stop in 215 m. Calculate its linear acceleration.(magnitude only)

2) Calculate its angular acceleration.(magnitude only)

3)The wheel's rotational inertia is 0.195 kg* m² about its central axis. Calculate the torque exerted by the friction on the wheel, about the central axis.(N*m) (magnitude only)

Solutions

Expert Solution

Radius r = 0.28 m

Initial speed u = 33 m/s

Final speed v = 0

Stoping distance S = 215 m

From the relation v ² - u ² = 2aS

Acceleration a = [v ² - u ² ] / 2S

= [0 ² - 33 ² ] /2(215)

= -2.532 m/s ²

Magnitude of acclration = 2.532 m/s ²

(2). Angular accleration = a / r

= 2.532 / 0.28

= 9.044 rad/s ²

genius_generous answered 1 year ago

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