In: Physics
A wheel of radius 0.280 m, which is moving initially at 33 m/s, rolls to a stop in 215 m. Calculate its linear acceleration.(magnitude only)
2) Calculate its angular acceleration.(magnitude only)
3)The wheel's rotational inertia is 0.195 kg* m2 about its central axis. Calculate the torque exerted by the friction on the wheel, about the central axis.(N*m) (magnitude only)
Radius r = 0.28 m
Initial speed u = 33 m/s
Final speed v = 0
Stoping distance S = 215 m
From the relation v 2 - u 2 = 2aS
Acceleration a = [v 2 - u 2 ] / 2S
= [0 2 - 33 2 ] /2(215)
= -2.532 m/s 2
Magnitude of acclration = 2.532 m/s 2
(2). Angular accleration = a / r
= 2.532 / 0.28
= 9.044 rad/s 2