Question

Write the c++ program of Secant Method and Fixed point Method in a one program using switch condition .Like :

cout<<"1.Secant Method \n 2. Fixed point Method\n"<<endl; if press 1 then work Secant Method if press 2 then work Fixed point Method .so please writhe the code in c++ using switch case.and the equation given down consider the equation in the given.Note: Must showt the all the step of output all the iteration step shown in the program .in program must shown all the step of iteration result

for secant method equation :4x3-2x-6=0

for fixed point=x2-x-1=0

Please in every itaration must be shown the output then finally Got the root

Answer 1

Secant Method

#include<iostream>
#include<iomanip>
#include<math.h>
#include<stdlib.h>
#define f(x) 4*x*x*x - 2*x - 6

using namespace std;

int main()
{
   float x0, x1, x2, f0, f1, f2, e;
   int step = 1, N;
cout<< setprecision(4)<< fixed;
   cout<<"Enter first guess: ";
   cin>>x0;
   cout<<"Enter second guess: ";
   cin>>x1;
   cout<<"Enter tolerable error: ";
   cin>>e;
   cout<<"Enter maximum iteration: ";
   cin>>N;  
   do
   {
       f0 = f(x0);
       f1 = f(x1);
       if(f0 == f1)
       {
           cout<<"Mathematical Error.";
           exit(0);
       }

       x2 = x1 - (x1 - x0) * f1/(f1-f0);
       f2 = f(x2);

       cout<<"Iteration-"<< step<<":\t x2 = "<< setw(10)<< x2<<" and f(x2) = "<< setw(10)<< f(x2)<< endl;

       x0 = x1;
       f0 = f1;
       x1 = x2;
       f1 = f2;

       step = step + 1;
   }while(fabs(f2)>e);

   cout<< endl<<"Root is: "<< x2;

   return 0;
}

Fixed point Method

#include<stdio.h>
#include<math.h>
#include<iostream>
#define g(x) (x+1)/(x)
using namespace std;
int main()
{
int k=0;
float x1,x0;
float eps = 1e-5;

cout<<"Enter the initial guess x0: ";
cin>>x0;
x1=x0;
do
{
k++;
x0=x1;
x1=g(x0);
cout<<"One root is obtained at:"<<k<<" is \t"<<x1;
cout<<"\n";
}while(fabs(x1-x0)>eps);
cout<<"Root is:" <<x0;
return 0;
}