Question

Orange    590（Peak Wavelength, nm）--- Photocurrent, mA (Current with zero stopping voltage)please anwers？--- Stopping voltage, V (Voltage to force current to zero)please anwers？   

     
Green      530（Peak Wavelength, nm） --- Photocurrent, mA (Current with zero stopping voltage)please anwers？--- Stopping voltage, V (Voltage to force current to zero)please anwers？    

                                                     
Blue        485（Peak Wavelength, nm）  --- Photocurrent, mA (Current with zero stopping voltage)please anwers？--- Stopping voltage, V (Voltage to force current to zero)please anwers？    

                                                  
Ultraviolet 445（Peak Wavelength, nm）    --- Photocurrent, mA (Current with zero stopping voltage)please anwers？--- Stopping voltage, V (Voltage to force current to zero)please anwers？

                                          

2/ Based on the graph with the best fit straight line, what can you say about the relationship betweenthe color (or frequency) of light and the energy of its separate bits or photons?

3/ Your value of Planck’s constant (h) from the Grapher: (     ? )                   J-s

The accepted value of Planck’s constant from Google:         ( ? )                J-s

Percent difference of your value from the accepted value:    ( ? ) %

Answer 1

Orange -    Photocurrent = 5/3.45

                                         = 1.449 mA

Stopping voltage, V = 5 V

Green -    Photocurrent = 4.5/3.34

                                         = 1.347 mA

Stopping voltage, V = 4.5 V

Blue -    Photocurrent = 4.2/3.23

                                         = 1.3 mA

Stopping voltage, V = 4.2 V

Ultraviolet -    Photocurrent = 4/3.12

                                         = 1.282 mA

Stopping voltage, V = 4 V

2)    the relationship between the color (or frequency) of light and the energy of its separate bits or photons - they are directly proportional to each other .

3)   value of Planck’s constant (h) from the Graph = 6.56 * 10^-34 J-s

       accepted value of Planck’s constant =   6.63 * 10^-34 J-s

=>   Percent difference   = (6.63 - 6.56)/6.63

                                     = 1.055 %