Question

In: Statistics and Probability

Suppose n unrelated families (defined as the husband, the wife, and one child) are gathered together....

Suppose n unrelated families (defined as the husband, the wife, and one child) are gathered together. What is the smallest n for which chances are > 50% that there will be two or more families completely matched in birthdays (i.e., the two husbands have the same birthday, so do the two wives, and so do the two children)?

Solutions

Expert Solution

There are n families.
Let X be an R.V. denoting the number of families with same birthdays.

Here,

In the following table, we iterate n for different values and check for which smallest n, the probability is greater than 0.5.

n p >.5
3 2.545E-05 False
4 5.08011E-05 False
5 8.45041E-05 False
6 0.00012651 False
7 0.00017677 False
8 0.000235236 False
9 0.000301859 False
10 0.000376592 False
11 0.000459386 False
12 0.000550194 False
13 0.000648968 False
14 0.000755662 False
20 0.00155951 False
30 0.003502039 False
40 0.006159485 False
45 0.007742867 False
50 0.009489094 False
100 0.034850112 False
500 0.428154126 False
575 0.499694604 False
576 0.500609221 TRUE
577 0.501522758 TRUE

It is observed that for n=576, the required probability is first greater than 0.5.

P.S. Here, I have taken days as Monday, Tuesday, ..., Sunday(ie. 7). If Birthday means out of 365 days, replace 7 by 365 and do the same steps.

I hope this answer helps you to a great extent. If you have any query, comment below. Hit the Like button if you' re satisfied. Thank You. :)


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