In: Statistics and Probability
Suppose n unrelated families (defined as the husband, the wife, and one child) are gathered together. What is the smallest n for which chances are > 50% that there will be two or more families completely matched in birthdays (i.e., the two husbands have the same birthday, so do the two wives, and so do the two children)?
There are n families.
Let X be an R.V. denoting the number of families with same
birthdays.
Here,
In the following table, we iterate n for different values and check
for which smallest n, the probability is greater than 0.5.
n | p | >.5 |
3 | 2.545E-05 | False |
4 | 5.08011E-05 | False |
5 | 8.45041E-05 | False |
6 | 0.00012651 | False |
7 | 0.00017677 | False |
8 | 0.000235236 | False |
9 | 0.000301859 | False |
10 | 0.000376592 | False |
11 | 0.000459386 | False |
12 | 0.000550194 | False |
13 | 0.000648968 | False |
14 | 0.000755662 | False |
20 | 0.00155951 | False |
30 | 0.003502039 | False |
40 | 0.006159485 | False |
45 | 0.007742867 | False |
50 | 0.009489094 | False |
100 | 0.034850112 | False |
500 | 0.428154126 | False |
575 | 0.499694604 | False |
576 | 0.500609221 | TRUE |
577 | 0.501522758 | TRUE |
It is observed that for n=576, the required probability is first
greater than 0.5.
P.S. Here, I have taken days as Monday, Tuesday, ...,
Sunday(ie. 7). If Birthday means out of 365 days, replace 7 by 365
and do the same steps.
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