Question

A certain stat teacher believes that her students should do at least an average of 5 hours of homework in a week. She took a random sample of stat students this semester. Their sample mean amount of homework time was 3.6 hours with a standard deviation of 1.8 hours. The sample size was 32. Test the state teacher’s claim that her students do at least an average of 5 hours of homework in a week at the 1% level of significance. Show calculations. state hypotheses; include sketch; answer in context.

Answer 1

Solution :-

Givan that ,

= 5

= 3.6

= 1.8

n = 32

This is the right tailed test .

The null and alternative hypothesis is ,

H0 :   = 5

Ha :    5  

Test statistic = z

= ( - ) / / n

= ( 3.6 - 5 ) / 1.8 / 32

= -4.40

The test statistic = -4.40

P - value = P( Z > -4.40 )

= 1 - P ( Z < -4.40 )

= 1 - 0.0000

= 1.0000

P-value = 1.0000

= 0.01

1.0000 > 0.01

P-value >  

Fail to reject the null hypothesis .

There is not sufficient evidence to claim