Question

In this example you are allowed to use from the C standard library only functions for input and output (e.g. printf(), scanf())

Complete the following functions using C programming language:

• intQ1_for()
• intQ1_while()
• intQ1_do()

To compute the sum of all numbers that are multiples of 4, between 30 and 1000, in three different ways: with a for loop, a while loop and a do-while loop, accordingly. After each loop print the value on the screen. Return the total sum at the end of each function

Answer 1

Code Explanation:

• Declare the functions
• In the main function with in the printf statement call the three functions
• In the Q1_for() function Initially declare sum =0,Then use for loop from 30 to 1000 and and check if i is divisible by 4 if yes then add it to sum
• After loop exists return sum
• In the Q1_while() initially initialize i =30 and sum =0.
• Run a while loop with condition 1<=1000. SO when i is greater than 1000 the loop exists else it checks the i%4==0 and if yes then adds the i to sum
• When loop exists return sum
• do while and while loop difference is here in do while first we perform the body part and then check condition

Code:

#include <stdio.h>
#include<conio.h>
int Q1_for();
int Q1_while();
int Q1_do();
void main()
{
printf("%d\n",Q1_for());
printf("%d\n",Q1_while());
printf("%d\n",Q1_do());

}

int Q1_for(){

int sum = 0, i;;
for(i = 30; i<=1000; i++){
if(i%4==0){
sum = sum +i;
}
}
return(sum);

}

int Q1_while(){

int i=30, sum = 0;
while(i<=1000){

if(i%4==0){
sum = sum+i;
}
i++;
}
return(sum);

}

int Q1_do(){

int i = 30, sum = 0, temp;
do{
if(i%4==0){
sum = sum + i;
}
i++;
}
while(i<=1000);

return(sum);
}

O/P:

125388
125388
125388

Code screenshot:

O/P screenshot:

(If you still have any doubts please comment I will definitely help)