In: Chemistry
you are instructed to add enough triethylene glycol (TEG) to make the solution 0.6 M in meso-stilbene dibromide. Suppose you 200 mg of meso-stilbene dibromide. What volume of TEG would be required?
Molarity of a solution = Number of moles of the solute present in 1 liter of the solution
= Number of moles of the solute / Volume of solution in liter
Molarity of a solution = Number of moles of the solute / Volume of solution in liter
OR
Volume of solution in liter = Number of moles of the solute / Molarity of the solution
Molarity of the solution = 0.6 M
CALCULATION OF NUMBER OF MOLES OF SOLUTE ,MESO- STILBENE DIBROMIDE
Mass of meso-stilbene dibromide = 200 mg = 0.200 g
Number of moles of meso-stilbene dibromide = Mass of meso-stilbene dibromide in gram / Molar mass
= 0.200 g / 339.8 g/mol = 0.00059 mol
Volume of solution in liter = Number of moles of the solute / Molarity of a solution
= ( 0.00059 mol / 0.6 M ) = 0.00098 L = 0.98 ml
0.98 ml of TEG would be required