Question

1. Write a java program which asks the user to enter name and age and calls the following methods:
   1. printName(): Takes name as parameter and prints it 20 times using a while loop.
   2. printAge(): Takes age as parameter and prints all the numbers from 1 up to age.

2. Write a java program that will print first 10 multiples of 3 in a single line.

Answer 1

1)Working of the code

• Using a Scanner object,name and age are read
• nextLine() method of Scanner class is used to read a line of string
• nextInt() method of scanner class is used to read an integer
• printName() and printAge() functions are called
• In printNmae() function,an integer i is declared and initialized with 1
• while loop executes its body as long as i is less than or equal to 20
• Inside loop body, name is printed and i is incremented by 1
• In printAge() function,an integer i is declared and initialized with 1
• while loop executes its body as long as i is less than or equal to age
• Inside loop body, i is printed and incremented by 1

source code

//Importing scanner class to accept user input
import java.util.Scanner;
public class Main {
    public static void main(String[] args) {
        //Creating Scanner object to read user input
        Scanner sc=new Scanner(System.in);
        //prompt user to enter name
        System.out.print("Enter name: ");
        //Reading the name
        String name=sc.nextLine();
        //prompt user to enter age
        System.out.print("Enter age: ");
        //Reading the age
        int age=sc.nextInt();
        //calling printName() method
        printName(name);
        //calling printAge() method
        printAge(age);
    }
    //printName() method definition
    public static void printName(String name)
    {
        //initializing  variable i to 1
        int i=1;
        //checking i is less than or equals to 20.if yes execute the loop body
        //if not, exit from the loop
        while (i<=20)
        {
            //printing name
            System.out.println(name);
            //incrementing i by 1
            i++;
        }
    }
    //printAge() method definition
    public static void printAge(int age)
    {
        //initializing  variable i to 1
        int i=1;
        //checking i is less than or equals to age.if yes execute the loop body
        //if not, exit from the loop
        while (i<=age)
        {
            //printing i
            System.out.println(i);
            //incrementing i by 1
            i++;
        }
    }
}

Screen shot of the program

Screen shot of the output

2) Working of the program

• Declare an integer variable i and initialize it with 1
• While loop executes its body as long as i is less than or equals to 10
• Inside loop,System.out.print() method is used to print multiple of 3 with a space after.
• increment i by 1 each time
• System.out.print() does not move to new line when each time it execute.It print values in the same line

Source code

public class Main {
    public static void main(String[] args) {
        //declare integer variable i and initialize with 1
        int i = 1;
        //Execute loop body as long as i is less than or equal to 10
        while (i <= 10) {
            //print multiple of i and put a space
            System.out.print(3 * i+" ");
            //increment i by 1
            i++;
        }
    }
}

Screen shot of the code

Screen shot of the output