X Frequency 135149.99 1 120134.99 0 105119.99 1 90104.99 1 75 89.99 2 60 74.99 5...

X Frequency 135149.99 1 120134.99 0 105119.99 1 90104.99 1 75 89.99 2 60 74.99 5 10 6. The unit of measurement equals a. 0.01 b. 1.00 c. 14.99 d. 15.00 7. The class interval width equals a. 14.99 b. 15 c. 60 d. none of the above 8. The overall appearance or shape of this distribution is a. balanced. b. lopsided. c. regular. d. impossible to determine from the information given. 9. The relative frequency of the interval 7589.99 equals a. 0.10 b. 0.20 c. 0.50 d. none of the above 10. The approximate percentile rank for the interval 90104.99 is a. 10 b. 70 c. 80 d. none of the above 11. If this frequency distribution represents the test scores for a class of ten college students, we can infer that the test probably is a. too easy. b. too difficult. c. multiple choice. d. essay.

Solutions

Expert Solution

Here the frequency of X is given as,

X	Frequency
135-149.99	1
120-134.99	0
105-119.99	1
90-104.99	1
75-89.99	2
60-74.99	5
Total	10

6. So the unit of measurement equals to the lowest degree of decimal that is considered as the increment unit for each values ( that is from 119.99 to 120) which is 0.01

Hence option a is the correct one.

7.The class interval width equals to (which is the difference of lower (or upper) limits of two consecutive classes) is 135-120=120-105=....=15

Hence option b is the correct one.

8. As we note that the frequency distribution has higher frequency for smaller valued classes and then it gradually decreases towards tail values hence the overall appearance or shape of this distribution is lopsided.

Hence option b is the correct one.

9. The relative frequency of the interval 75-89.99 equals is (frequency/total frequency)=2/10=0.2

Hence option b is the correct one.

10. The approximate percentile rank for the interval 90-104.99 is

[(total frequency below or equal to the class)/(total frequency)]*100

11. If this frequency distribution represents the test scores for a class of ten college students, we can infer that the test probably is too difficult as there most of the students scored lower values

Hence option b is the correct one.

hence the answer.............

thank you.............

orchestra answered 1 year ago

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