In: Math
Assume that the systolic blood pressure of 30-year-old males is normally distributed, with an average of 122 mmHg and a standard deviation of 10 mmHg.
A random sample of 16 men from this age group is selected. Calculate the probability that the average blood pressure of the sample will be greater than 125 mmHg.
The population is normally distributed, so sample means are also normally distributed for any sample size. Calculate the standard error of the mean = 10 / SQRT(16) = 2.5. Calculate the z-score for the sample mean, X Bar = 125.
So take (125-122) /2.5 = 1.2. Therefore, z=1.20 now you need to find a reference table for z.
According to normal standard table it is 0.3849. The area below
the curve on each side of the mean is 0.5, and the area
between
the mean and the z-score 1.20 is 0.3849. Calculate the probability
that the average blood pressure of the sample will be greater than
125 mmHg: = 0.5 - 0.3849 = 0.1151 or 11.51%.
I hope this helped as a practical application.