Question

C CODE PLZ! All instructions for what to do in code

#include <stdio.h>


int main(int argc, char **argv) {
  int n, k, l, r, t, d, i;
  char str[65];

  /* Make the user enter a non-negative integer */
  printf("Please enter a non-negative integer: ");
  scanf("%d", &n);
  while (n < 0) {
    printf("Sorry, your input is incorrect.\n");
    printf("Please enter a non-negative integer: ");
    scanf("%d", &n);
  }

  /* Convert the integer to reversed binary: e.g. 6 gets converted to 011 */
  if (n == 0) {
    /* Special case for n = 0 */
    str[0] = '0';
    str[1] = '\0';
  } else {
    /* Common case */
    k = n;
    
    /* TODO */
  }

  /* The conversion made the string come out reversed, so reverse the string again. 

     DO NOT USE A COPY OF THE STRING. DO NOT USE ANY LIBRARY FUNCTION
     (no strlen or other !)

  */
  
  /* TODO */
  
  /* Display the number and the string */
  printf("The decimal number %d is %s in binary.\n", n, str);
  
  return 0;
}

Answer 1

Code

#include <stdio.h>

int main(int argc, char **argv) {

int n, k, l, r, t, d, i;

char str[65],c;

/* Make the user enter a non-negative integer */

printf("Please enter a non-negative integer: ");

scanf("%d", &n);

while (n < 0) {

printf("Sorry, your input is incorrect.\n");

printf("Please enter a non-negative integer: ");

scanf("%d", &n);

}

/* Convert the integer to reversed binary: e.g. 6 gets converted to 011 */

if (n == 0) {

/* Special case for n = 0 */

str[0] = '0';

str[1] = '\0';

} else {

/* Common case */

k = n;

i=0;

while(k>0)

{

if(k%2==0)

str[i]='0';

else

str[i]='1';

k=k/2;

i++;

}

str[i]='\0';

}

/* TODO */

l = 0;

k =i-1;

while (l < k) {

c = str[l];

str[l] = str[k];

str[k] = c;

l++;

k--;

}

/* Display the number and the string */

printf("The decimal number %d is %s in binary.\n", n, str);

return 0;

}

output

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