Question

Instructions: Create a Java program that reads a string entered by the user and then determines and prints how many of each lowercase vowel (a, e, i, o, and u) appear in the entire string. Have a separate counter for each vowel. Also, count and print the number of non-vowel characters.

Example: User enters: "This house is beautiful."

a: 1

e: 2

i: 3

o: 1

u: 2

non-vowel:10

Answer 1

The Solution:

import java.util.Scanner; //for accepting input
public class Main
{
   public static void main(String[] args) {
   //inntializing variables for count n input string
int aCount = 0, eCount = 0, iCount = 0;
int oCount = 0, uCount = 0, nonVowelCount = 0;
String userString;
  
//getting the string from user
Scanner sc = new Scanner (System.in);
System.out.println("Enter a string:");
userString = sc.nextLine();
  
for (int i = 0; i < userString.length(); i++) {
//reach each character of string and checking
char ch = userString.charAt(i);
  
if (ch== 'a') aCount++; //checking vowel 'a'   
else if (ch== 'e') eCount++; //checking vowel 'e'
else if (ch== 'i') iCount++; //checking vowel 'i'
else if (ch== 'o') oCount++; //checking vowel 'o'
else if (ch== 'u') uCount++; //checking vowel 'u'
//checking non-vowels
else if ((ch >= 'a'&& ch <= 'z')||(ch >= 'A'&& ch <= 'Z')) nonVowelCount++;   
}
  
//displaying the count of each vowel and non-vowels
System.out.println("a: " + aCount + "\n" +
"e: " + eCount + "\n" +
"i: " + iCount + "\n" +
"o: " + oCount + "\n" +
"u: " + uCount + "\n" +
"non-vowel:" + nonVowelCount);
}
}

The Screenshots:

The Code:

The Output: