Use Laplace transforms to solve the following initial value problem : y'' - 3y' +2y =...

Use Laplace transforms to solve the following initial value problem :

y^'' - 3y^' +2y = 1 + cos (t) + e^t , y(0) =1, y' (0) = 0

Colby Messinger answered 2 years ago

Use Laplace Transforms to solve the Initial Value Problem: y "+ 3y '+ 2y = 12e^(2x); y (0) = 1, y' (0) = –1.

Use Laplace transforms to solve the initial value problem: x' = 2x + y, y' = 6x + 3y; x(0) = 1, y(0) = -2

Use Laplace transforms to solve the initial value problem: y''' −y' + t = 0, y(0) = 0, y'(0) = 0, y''(0) = 0.

Use the Laplace transform to solve the given initial-value problem. y'' - 2y'' - 8y = 2sin2t; y(0) = 2, y'(0) = 4

Use the Laplace transform to solve the given initial value problem. y'' + 2y' + 10y = 6cos2t - 4sin2t, y(0)=2, y'(0)= -2

solve the given initial value problem using the method of Laplace transforms. Y'' + Y = U(t-4pi) y(0) =1 y'(0) = 0

Solve the initial value problem below using the method of Laplace transforms. y'' - 4y' + 8y = 5e^t y(0) = 1 y'(0) = 3

. Solve the Initial value problem by using Laplace transforms: ? ′′ + 3? ′ + 2? = 6? −? , ?(0) = 2 ? ′ (0) = 8

Solve the following initial value problem using Laplace transforms: y000 + y0 = et, y(0) = y0(0) = y00(0) = 0.

Solutions