In: Statistics and Probability
The temperature in degrees Fahrenheit and the number of emergency calls are shown below. Determine if there is a relationship between the temperature and the number of emergency calls received. Use .05 significance.
Number of Calls (Y) |
Temperature (X) |
7 |
68 |
4 |
74 |
8 |
82 |
10 |
88 |
11 |
93 |
9 |
99 |
13 |
101 |
What is the p value and is it significant?
Select one:
a. .1898, no it is not significant.
b. .0267, yes it is significant.
c. .2162, yes it is significant.
d. 9.6335, yes it is significant.
The temperature in degrees Fahrenheit and the number of emergency calls are shown below. Determine if there is a relationship between the temperature and the number of emergency calls received. Use .05 significance.
Number of Calls (Y) |
Temperature (X) |
7 |
68 |
4 |
74 |
8 |
82 |
10 |
88 |
11 |
93 |
9 |
99 |
13 |
101 |
If x is equal to 80, what is the value of y?
Select one:
a. Unable to determine because the relationship is not significant.
b. 7.0.
c. 7.6399.
d. 8.1088.
We use the regression model to find the relationship between the temprature and emergency calls received.
Below is the regression output of Excel.
SUMMARY OUTPUT |
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Regression Statistics |
||||||
Multiple R |
0.811369 |
|||||
R Square |
0.658319 |
|||||
Adjusted R Square |
0.589983 |
|||||
Standard Error |
1.864238 |
|||||
Observations |
7 |
|||||
ANOVA |
||||||
df |
SS |
MS |
F |
Significance F |
||
Regression |
1 |
33.48022 |
33.48022 |
9.633531 |
0.026738 |
|
Residual |
5 |
17.37692 |
3.475384 |
|||
Total |
6 |
50.85714 |
||||
Coefficients |
Standard Error |
t Stat |
P-value |
Lower 95% |
Upper 95% |
|
Intercept |
-7.5441 |
5.331028 |
-1.41513 |
0.216184 |
-21.2479 |
6.159745 |
X Variable 1 |
0.189766 |
0.06114 |
3.103793 |
0.026738 |
0.032601 |
0.346932 |
1. From the output of regression,
The P value = 0.0267
P value < 0.05 so we reject null hypothesis 5% level of significance.
We conclude that it is significant.
2. From the above output,
Regression equation is Y = 0.1898*X – 7.5441
If X = 80 then the value of Y = 0.1898*80 – 7.5441 = 7.6399
The value of Y = 7.6399.