In: Physics
1. Determine which of the following statements is true about electric field lines in the vicinity of two point charges of equal magnitude and opposite sign.
a. they are small according to the magnitude of the loads decrease b. indicate the relative magnitude of the electric field c. is larger as the magnitude of the loads increases d. does not depend on the magnitude of the loads e. indicates the direction of the electric field
2. An electric field causes an electron to move east. The direction of the electric field is towards.
a. East b.South c. North d. West
3. An electric field has a magnitude of 2,160 N / C. If the force on a load is 0.01296 N, determine the magnitude of the load
a. 11 microCoulomb
b. 2 microCoulomb
c. 6 microCoulomb
d. 9 microCoulomb
e. 4 microCoulomb
4. The electric field at 2.0 m from a strut charge has a magnitude of 80,000 N / C. Determine the intensity of the electric field at a distance of 4.0 m.
a. 40,000 N/C
b. 160,000 N/C
c. 320,000 N/C
d. 20,000 N/C
1. Answer: e. indicates the direction of the electric field
Explanation: electric field lines between two point charges indicates the direction of the electric field between them
2. Answer: d. West
Explanation: Electric field lines are always from positive charge to negative charge. Electron being a negative charge always attracted by the positive charge . As the electron is moving to East , positive charge is in the East and negative charge is in the west . So magnetic field directed to the West.
3. Answer: c. 6 micro Coulomb
Solution: Load = Force/ Electric field = 0.01296 /2160 = 6 X 10 ^-6 C = 6 micro Coulomb
4. Answer:d. 20000 N/C
Explanation: As the electric field intensity is inversely proportional to the square of the distance , magnitude of the intensity will be 1/4 th as the distance increased by factor 2 .
so Magnitude will be 80000/4 N/C = 20000 N/C
Thank You.