In: Statistics and Probability
3. The following table contains data on health assessment for a random sample of 32 cases from the GSS 2006. Health is measured according to a four-point scale: 1 = excellent, 2 = good, 3 = fair, and 4 = poor. Four social classes are reported here: lower, working, middle, and upper. Using = 0.05, test the null hypothesis that there is no difference between the groups. State very clear your hypothesis and your conclusions. You can use Excel to solve this one, but if you use Excel you must provide the output. lower class: 3,2,2,2,3,3,4,4 working class: 2,1,3,2,2,2,3,3 middle class: 2,3,1,1,2,3,3,1 upper class: 2,1,1,2,1,1,1,2
1. Arrange the data in excel as shown below.
2. Select one-factor ANOVA from the data analysis tab.
3. Input the value as shown.
4. The output will be generated as follows.
Hypothesis.
Ho: The mean health assessment score in the 4 different class is
equal.
H1: The mean health assessment score in the 4 different class is
not equal.
From the ANOVA output, we look at the pvalue which is
0.005(highlighted in yellow). Since the pvalue is less than 0.05,
we reject the null hypothesis and conclude that the mean health
assessment score in the 4 different class is not equal.