In: Statistics and Probability
If you win $100 for rolling a 12, win $10 for rolling a number less than 6, and lose $4 for rolling anything else, what are your expected winnings per play?
a. $1.94 b. $4.72 c. $2.78 d. -$.68
A committee of 7 is be selected from a group of 22 people. How many such committees are possible?
a. 22,254 b. 319,770 c, 170,544 d. 101,458
A woman plans on having four children. What is the probability she will have at most 2 boys?
a. 11/16 b. 1/2 c. 9/16 d. 6/16
Thirty-nine percent of the houses in a certain neighborhood read the New Yorker, 43 percent read the Philadelphia Inquirer, and 9 percent read both. What percent read at least one of these publications?
a. 64% b. 79% c. 82% d. 73%
What is the probability of getting at least one 10 in twenty rolls of a pair of dice?
a. (33/36)20 b. 1-(3/36)20 c. 1- (33/36)20 d. 1-20(33/36)
A.
X | 100 | 10 | -4 |
P(X) | 1/36 | 10/36 | 25/36 |
The probability of obtaining a sum of 12 is 1/36.
The probability of obtaining a sum of less than 6 is 10/36.
The probability of obtaining anything else is 25/36.
The expected winnings per play is $ 2.78.
E(X) = 100*(1/36)+ 10*(10/36)- 4*(25/36) = 2.777778 ~ $ 2.78
C option is the correct answer.
B.
A committee of 7 is to be selected from a group of 22 people.
It can be done in
C option is the correct answer.
C.
P(read the New Yorker) = 0.39
P(read the Philadelphia Inquirer) = 0.43
P( read both the publications) = 0.09
P(read at least these publications) =??
Using the formula, P(AUB) = P(A) + P(B) - P(A B)
P(read at least these publications)
= P(read the New Yorker) + P(read the Philadelphia Inquirer) - P( read both the publications)
= 0.39 + 0.43 - 0.09 = 0.73
73% read at least these publications.
D option is the correct answer.
D.
The probability of obtaining a 10 is 3/36.
Now out of 20 rolls, we need to find the probability of getting at least one 10 in twenty rolls of a pair of dice.
P(X 1) = 1 - P(X<1) = 1 - P(X = 0) = 1 - P(None) =
= 0.8245195
C option is the correct answer.