In: Operations Management
Problem 13-09 (Algorithmic)
Myrtle Air Express decided to offer direct service from Cleveland to Myrtle Beach. Management must decide between a full-price service using the company’s new fleet of jet aircraft and a discount service using smaller capacity commuter planes. It is clear that the best choice depends on the market reaction to the service Myrtle Air offers. Management developed estimates of the contribution to profit for each type of service based upon two possible levels of demand for service to Myrtle Beach: strong and weak. The following table shows the estimated quarterly profits (in thousands of dollars):
Demand for Service | ||
Service | Strong | Weak |
Full price | $1320 | -$550 |
Discount | $980 | $440 |
Optimistic approach | |
Conservative approach | |
Minimax regret approach |
a.
The decision that has to be made is to choose between full price or discounted service.
There are two decision alternatives
There are two outcomes for the chance event
b.
Optimistic approach: this is also called maximax approach. The maximum value for each decision alternative is 1320 and 980. Among them 1320 is more optimistic. Hence we will choose Full price service.
Conservative approach: this is also called maximin approach. The minimum value for each decision alternative is -550 and 440. Among the better option is 440. Hence we will choose Discount service.
Minimax regret: if we choose full price and the demand is strong then the regret is 0. However if we choose discount and the demand is strong then the regret is 1320-980=340. Similarly if we choose full price and the demand is weak, the regret is 440-(-550) = 990. On the other hand if we choose discount and the demand is weak, there is no regret.
Now the maximum regret for Full price service decision is 990. The maximum regret for the discount service is 340. Among them the minimum regret is with discount service.
The minimax regret approach dictates that we should provide discounted service.
c.
Expected value approach: determine the sum of product between probabilities and payoffs for each decision.
Full price = 0.7*1320 + 0.3*(-550) = 759
Discount = 0.7*980 + 0.3*440 = 818
The higher value is expected with discounted service as per the expected value method and that will be the optimal decision.
d.
Recalculating using the new probabilities,
Full price = 0.8*1320 + 0.2*(-550) = 946
Discount = 0.8*980 + 0.2*440 = 872
The optimal decision now is to offer full priced service.
e.
Let the probability of strong demand be X. We have already seen that X as an equilibrium point falls between 0.7 and 0.8. Thus
X*1320 + (1-X)*(-550) = X*980 + (1-X)*440
1320X – 980X = (1-X)*(440 + 550)
340X = 990 – 990X
X = 990/(990+340) = 0.744
The equilibrium point is 0.744 probability for the strong demand.
Discounted price service is the best option if the strong demand is less than or equal to 0.744. For values greater than this, the full price is the right choice