In: Statistics and Probability
Mist (airborne droplets or aerosols) is generated when metal-removing fluids are used in machining operations to cool and lubricate the tool and work-piece. Mist generation is a concern to OSHA, which has recently lowered substantially the workplace standard. The article "Variables Affecting Mist Generation from Metal Removal Fluids" (Lubrication Engr., 2002: 10-17) gave the accompanying data on x = fluid flow velocity for a 5% soluble oil (cm/sec) and y = the extent of mist droplets having diameters smaller than some value:
x: 89 177 189 354 362 442 965
y: .40 .60 .48 .66 .61 .69 .99
d. Estimate the true average change in mist associated with a 1 cm/sec increase in velocity, and do so in a way that conveys information about precision and reliability. Hint: This question is asking for a CI for beta. Compute it AND interpret it. By hand; i.e. you must use the basic formulas for the CI. E.g. for beta: beta_hat +- t* s_e/sqrt(S_xx) , but you may use R to compute the various terms in the formula. Use 95% confidence level.
e. Suppose the fluid velocity is 250 cm/sec. Compute an interval estimate of the corresponding mean y value. Use 95% confidence level. Interpret the resulting interval. By hand, as in part d.
f. Suppose the fluid velocity for a specific fluid is 250 cm/sec. Predict the y for that specific fluid in a way that conveys information about precision and reliability. Use 95% prediction level. Interpret the resulting interval. By hand, as in part d.
The regression equation is
y = 0.4041 + 0.00062 x
Predictor | Coef | SE Coef | T | P |
Constant | 0.40412 | 0.03459 | 11.68 | 0.000 |
x | 0.00062 | 0.00007579 | 8.19 | 0.000 |
S = 0.0540453 R-Sq = 93.1% R-Sq(adj) = 91.7%
x | y | (x-X_)^2 |
89 | 0.4 | 32144.9041 |
177 | 0.6 | 8333.8641 |
189 | 0.48 | 6286.9041 |
354 | 0.66 | 7346.2041 |
362 | 0.61 | 8781.5641 |
442 | 0.69 | 30175.1641 |
965 | 0.99 | 485404.8241 |
Sxx= | 578473.4287 |