In: Statistics and Probability
A clinical trial is run to investigate the effectiveness of an experimental drug in reducing preterm delivery to a drug considered standard care and to placebo. Pregnant women are enrolled and randomly assigned to receive either the experimental drug, the standard drug or placebo. Women are followed through delivery and classified as delivering preterm (< 37 weeks) or not. The data are shown below.
Preterm Delivery |
Experimental Drug |
Standard Drug |
Placebo |
Yes |
20 |
32 |
36 |
No |
80 |
68 |
64 |
a) Is there a statistically significant difference in the proportions of women delivering preterm among the three treatment groups? Run the test at a 5% level of significance.(hint: χ2 test) (10 points)
Ho: VS H1:
Compute : χ2 (7 points):
P-value(1 point)
Conclusion(1 points):
Accept H0 Reject H0
Ho:
there is no difference in the proportions of women delivering preterm among the three treatment groups
Ha: there is a statistically significant difference in the proportions of women delivering preterm among the three treatment groups
Applying chi square test:
Oi | Experimental | Standard Drug | Placebo | Total | |
Yes | 20 | 32 | 36 | 88 | |
not meet | 80 | 68 | 64 | 212 | |
total | 100 | 100 | 100 | 300 | |
Expected | Ei=row total*column total/grand total | Experimental | Standard Drug | Placebo | Total |
Yes | 29.333 | 29.333 | 29.333 | 88 | |
not meet | 70.667 | 70.667 | 70.667 | 212 | |
total | 100 | 100 | 100 | 300 | |
chi square χ2 | =(Oi-Ei)2/Ei | Experimental | Standard Drug | Placebo | Total |
Yes | 2.9697 | 0.2424 | 1.5152 | 4.727 | |
not meet | 1.2327 | 0.1006 | 0.6289 | 1.962 | |
total | 4.202 | 0.343 | 2.144 | 6.6895 |
χ2 =6.6895
degree of freedom(df) =(rows-1)*(columns-1)= | 2 |
for 2 degree of freedom and above test statistic ; p value =0.0353
Conclusion:Reject Ho