In: Statistics and Probability
Use the data in Problem 1:
Percent Wound Healing |
||||
Treatment |
0-25% |
26-50% |
51-75% |
76-100% |
New Compound (n=125) |
15 |
37 |
32 |
41 |
Placebo (n=125) |
36 |
45 |
34 |
10 |
and pool the data across the treatments into one sample of size n= 250. Use the pooled data to test whether the distribution of the percent wound healing is approximately normal. Specifically, use the following distribution: 30%, 40%, 20%, and 10% and a= 0.05 to run the appropriate test.
Percent Wound Healing |
|||||
Treatment |
0-25% |
26-50% |
51-75% |
76-100% |
Total |
Number of Patients |
51 |
82 |
66 |
51 |
250 |
pool the data across the treatments into one sample of size n= 250. Use the pooled data to test whether the distribution of the percent wound healing is approximately normal. Specifically, use the following distribution: 30%, 40%, 20%, and 10% and a= 0.05 to run the appropriate test.
Percent Wound Healing |
|||||
Treatment |
0-25% |
26-50% |
51-75% |
76-100% |
Total |
Number of Patients |
51 |
82 |
66 |
51 |
250 |
Goodness of Fit Test |
||||
observed |
expected |
O - E |
(O - E)² / E |
|
51 |
75.000 |
-24.000 |
7.680 |
|
82 |
100.000 |
-18.000 |
3.240 |
|
66 |
50.000 |
16.000 |
5.120 |
|
51 |
25.000 |
26.000 |
27.040 |
|
Total |
250 |
250.000 |
43.080 |
|
43.08 |
chi-square |
|||
3 |
df |
|||
0.0000 |
p-value |
Calculated chi square =43.08
DF=4-1=3
Critical Chi square value at 0.05 level =7.815
Calculated chi square =43.08 > 7.815 the table value.
The null hypothesis is rejected.
We conclude the data is different from the given distribution.