In: Statistics and Probability
Use the data in Problem 1:
| 
 Percent Wound Healing  | 
||||
| 
 Treatment  | 
 0-25%  | 
 26-50%  | 
 51-75%  | 
 76-100%  | 
| 
 New Compound (n=125)  | 
 15  | 
 37  | 
 32  | 
 41  | 
| 
 Placebo (n=125)  | 
 36  | 
 45  | 
 34  | 
 10  | 
and pool the data across the treatments into one sample of size n= 250. Use the pooled data to test whether the distribution of the percent wound healing is approximately normal. Specifically, use the following distribution: 30%, 40%, 20%, and 10% and a= 0.05 to run the appropriate test.
| 
 Percent Wound Healing  | 
|||||
| 
 Treatment  | 
 0-25%  | 
 26-50%  | 
 51-75%  | 
 76-100%  | 
 Total  | 
| 
 Number of Patients  | 
 51  | 
 82  | 
 66  | 
 51  | 
 250  | 
pool the data across the treatments into one sample of size n= 250. Use the pooled data to test whether the distribution of the percent wound healing is approximately normal. Specifically, use the following distribution: 30%, 40%, 20%, and 10% and a= 0.05 to run the appropriate test.
| 
 Percent Wound Healing  | 
|||||
| 
 Treatment  | 
 0-25%  | 
 26-50%  | 
 51-75%  | 
 76-100%  | 
 Total  | 
| 
 Number of Patients  | 
 51  | 
 82  | 
 66  | 
 51  | 
 250  | 

| 
 Goodness of Fit Test  | 
||||
| 
 observed  | 
 expected  | 
 O - E  | 
 (O - E)² / E  | 
|
| 
 51  | 
 75.000  | 
 -24.000  | 
 7.680  | 
|
| 
 82  | 
 100.000  | 
 -18.000  | 
 3.240  | 
|
| 
 66  | 
 50.000  | 
 16.000  | 
 5.120  | 
|
| 
 51  | 
 25.000  | 
 26.000  | 
 27.040  | 
|
| 
 Total  | 
 250  | 
 250.000  | 
 43.080  | 
|
| 
 43.08  | 
 chi-square  | 
|||
| 
 3  | 
 df  | 
|||
| 
 0.0000  | 
 p-value  | 
|||
Calculated chi square =43.08
DF=4-1=3
Critical Chi square value at 0.05 level =7.815
Calculated chi square =43.08 > 7.815 the table value.
The null hypothesis is rejected.
We conclude the data is different from the given distribution.