In: Statistics and Probability
27% of all college students major in STEM (Science, Technology, Engineering, and Math). If 45 college students are randomly selected, find the probability that
a. Exactly 13 of them major in STEM.
b. At most 12 of them major in STEM.
c. At least 9 of them major in STEM.
d. Between 8 and 15 (including 8 and 15) of them major in STEM.
Using Normal Approximation
Mean = n * P = ( 45 * 0.27 ) = 12.15
Variance = n * P * Q = ( 45 * 0.27 * 0.73 ) = 8.8695
Standard deviation = √(variance) = √(8.8695) = 2.9782
Part a)
P ( X = 13 )
Using continuity correction
P ( n - 0.5 < X < n + 0.5 ) = P ( 13 - 0.5 < X < 13 +
0.5 ) = P ( 12.5 < X < 13.5 )
X ~ N ( µ = 12.15 , σ = 2.9782 )
P ( 12.5 < X < 13.5 )
Standardizing the value
Z = ( X - µ ) / σ
Z = ( 12.5 - 12.15 ) / 2.9782
Z = 0.12
Z = ( 13.5 - 12.15 ) / 2.9782
Z = 0.45
P ( 0.12 < Z < 0.45 )
P ( 12.5 < X < 13.5 ) = P ( Z < 0.45 ) - P ( Z < 0.12
)
P ( 12.5 < X < 13.5 ) = 0.6736 - 0.5478
P ( 12.5 < X < 13.5 ) = 0.1259
Part b)
P ( X <= 12 )
Using continuity correction
P ( X < n + 0.5 ) = P ( X < 12 + 0.5 ) = P ( X < 12.5
)
X ~ N ( µ = 12.15 , σ = 2.9782 )
P ( X < 12.5 )
Standardizing the value
Z = ( X - µ ) / σ
Z = ( 12.5 - 12.15 ) / 2.9782
Z = 0.12
P ( ( X - µ ) / σ ) < ( 12.5 - 12.15 ) / 2.9782 )
P ( X < 12.5 ) = P ( Z < 0.12 )
P ( X < 12.5 ) = 0.5478
Part c)
P ( X >= 9 )
Using continuity correction
P ( X > n - 0.5 ) = P ( X > 9 - 0.5 ) =P ( X > 8.5 )
X ~ N ( µ = 12.15 , σ = 2.9782 )
P ( X > 8.5 ) = 1 - P ( X < 8.5 )
Standardizing the value
Z = ( X - µ ) / σ
Z = ( 8.5 - 12.15 ) / 2.9782
Z = -1.23
P ( ( X - µ ) / σ ) > ( 8.5 - 12.15 ) / 2.9782 )
P ( Z > -1.23 )
P ( X > 8.5 ) = 1 - P ( Z < -1.23 )
P ( X > 8.5 ) = 1 - 0.1093
P ( X > 8.5 ) = 0.8907
Part d)
P ( 8 <= X <= 15 )
Using continuity correction
P ( n - 0.5 < X < n + 0.5 ) = P ( 8 - 0.5 < X < 15 +
0.5 ) = P ( 7.5 < X < 15.5 )
X ~ N ( µ = 12.15 , σ = 2.9782 )
P ( 7.5 < X < 15.5 )
Standardizing the value
Z = ( X - µ ) / σ
Z = ( 7.5 - 12.15 ) / 2.9782
Z = -1.56
Z = ( 15.5 - 12.15 ) / 2.9782
Z = 1.12
P ( -1.56 < Z < 1.12 )
P ( 7.5 < X < 15.5 ) = P ( Z < 1.12 ) - P ( Z < -1.56
)
P ( 7.5 < X < 15.5 ) = 0.8686 - 0.0594
P ( 7.5 < X < 15.5 ) = 0.8093