In: Physics
The drawing shows an exaggerated view of a rifle that has been ‘sighted in' for a 91.4-meter target. If the muzzle speed of the bullet is v0 = 475 m/s, there are the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target. One of these angles is so large that it is never used in target shooting. Give your answers as (a) the smaller angle and (b) the larger angle. (Hint: The following trigonometric identity may be useful: 2 sinθ cosθ = sin 2θ.)
I have been able to get to sin2θ = (9.8m/s^2) (91.4m) / (475 m/s)^2 but i am not sure what to do from here and keep getting the answer wrong.
I hope you understood the problem and got your answers, If yes rate me!! or else comment for a better solutions