Question

In: Statistics and Probability

You survey 1012 Americans and find that 587 support legalizing marijuana. What is your estimate of...

You survey 1012 Americans and find that 587 support legalizing marijuana. What is your estimate of the percent of Americans who support legalizing marijuana? What is a 95% confidence interval on your estimate?

Solutions

Expert Solution

Solution :

Given that,

n = 1012

x = 587

Point estimate = sample proportion = = x / n = 587 / 1012 = 0.580

1 - = 1 - 0.580 = 0.420

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 1.96 * (((0.580 * 0.420) / 1012)

= 0.030

A 95% confidence interval for population proportion p is ,

- E < p < + E

0.580 - 0.030 < p < 0.580 + 0.030

0.550 < p < 0.610

The 95% confidence interval for the population proportion p is : (0.550 , 0.610)


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