In: Chemistry
A solution contains 21.1 grams of NaCl in 0.721 kg water at 25 °C. What is the vapor pressure of the solution?
vapor pressure of solution = vapor pressure of solvent * mole fraction of solvent
Psolution = P0 * X solvent
no of moles of water ( n water) = 721/18 = 40.05moles
no of moles of NaCl ( n NaCl) = 21.1/58.5 = 0.36 moles
mole fraction of water (Xwater) = n water/n water + n NaCl
= 40.05/40.05 + 0.36
= 40.05/40.41 = 0.991
The vapor pressure of water at 250C = 23.8 torr
Ps = P0* Xsolvent
= 23.8*0.991 = 23.586 torr >>>answer