The trajectory of a rock ejected from the Kilauea volcano, with a velocity of magnitude 46.9...

The trajectory of a rock ejected from the Kilauea volcano, with a velocity of magnitude 46.9 m/s and at angle 35.1 degrees above the horizontal. The rock strikes the side of the volcano at an altitude of 39.1m lower than its starting point. Calculate the magnitude of the rock’s velocity at impact? Use g = 9.8 m/s².

Solutions

Expert Solution

The total mechanical energy of the volcano + rock system would be conserved, i.e., mechanical energy at point A equals to mechanical energy at B. The volcano is neither moving nor changing it's position hence, it's change in mechanical energy is zero, thus, we have to just calculate the mechanical energy of rock at points A and B.

genius_generous answered 5 months ago

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