Question

Create a java random program from example (1,2,3,4,5,6,7,8,9,10) But do exception for number 7 when you run the program first time for example it will print 3 then when you run the program for the second time it will give a random number for example 9 but number 7 will not be printed because we need you to do exception for it.

Answer 1

I have uploaded the Images of the code, Typed code and Output of the Code. I have provided explanation using comments(read them for better understanding).

Images of the Code:

Note: If the below code is missing indentation please refer code Images

Typed Code:

//packages
import java.lang.Math.*;
public class Main
{
   public static void main(String[] args) {
   //taking min value = 1 and max value = 10
       int min = 1;
       int max = 10;
       //taking Random number in given range
       //math.random() is greater than or equal to 0.0 and less than 1.0
       //for example:- random number = 0.1
       //0.1*(10-1)+1 ==> 0.1*9+1 ==> 10
       int rand = (int) ((Math.random() * (max - min)) + min);
       System.out.print("Random Number: ");
       //if rand not equal to 7
       if(rand != 7)
       {
       //then printing the number
       System.out.println(rand);
       }
   }
}
//code ended here

Output:

Here Random number is 9, so printed

Here Random number is 7, so it will not be printed

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