Question

In: Physics

Suppose a tank contains 787 m3 of neon (Ne) at an absolute pressure of 1.01×105 Pa....

Suppose a tank contains 787 m3 of neon (Ne) at an absolute pressure of 1.01×105 Pa. The temperature is changed from 293.2 to 294.7 K. What is the increase in the internal energy of the neon?

Solutions

Expert Solution

Solution:

Given data

temperature is changed from 293.2 to 294.7 K

Increase in the internal energy of the neon:

The change in internal energy of a gas is

we assume the neon perfect in terms of Calorically ,then the above equation can also be written as

  • where n =  number of moles of gas
  • cv =  molar isotropic specific heat of the gas
  • T1 = Initial temperature
  • T2= Final Temperature
  • =  change in internal energy of a gas

cv is expressed in terms of the gas constant R , when it exists mono atomically on the sun, k=5/3.

above expression is substitute in equation-(1)

By using the Ideal gas law

above n*R value substitute in equation(2)

Now we know all values so substitute in above expression then find the internal energy of a gas is

we know that 1 k Pa * 1m3 = 1 kilo Joules.

.


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