Question

In: Statistics and Probability

A sociologist is interested in the relation between x = number of job changes and y...

A sociologist is interested in the relation between x = number of job changes and y = annual salary (in thousands of dollars) for people living in the Nashville area. A random sample of 10 people employed in Nashville provided the following information.

x (number of job changes) 4 3 6 6 1 5 9 10 10 3
y (Salary in $1000) 35 37 36 32 32 38 43 37 40 33

In this setting we have Σx = 57, Σy = 363, Σx2 = 413, Σy2 = 13,289, and Σxy = 2137.

(a)Find Se. (Round your answer to three decimal places.)

(b) Find a 90% confidence interval for the annual salary of an individual with x = 5 job changes. (Round your answers to two decimal places.)

1) lower limit

2) upper limit

(c) Test the claim that the slope β of the population least-squares line is positive at the 5% level of significance. (Round your test statistic to three decimal places.) t =

(l) Find a 90% confidence interval for β and interpret its meaning. (Round your answers to three decimal places.)

1) lower limit

2) upper limit

Solutions

Expert Solution

n= 10.0000
X̅=ΣX/n 5.7000
Y̅=ΣY/n 36.3000
sx=(√(Σx2-(Σx)2/n)/(n-1))= 3.1287
sy=(√(Σy2-(Σy)2/n)/(n-1))= 3.5292
Cov=sxy=(ΣXY-(ΣXΣY)/n)/(n-1)= 7.5444
r=Cov/(Sx*Sy)= 0.6832
slope= β̂1 =r*Sy/Sx= 0.7707
intercept= β̂0 ='y̅-β1x̅= 31.9069

a)

Se =√(SSE/(n-2))= 2.733

b)

predicted val=31.907+5*0.771= 35.76
standard error of PI=s*√(1+1/n+(x0-x̅)2/Sxx)= 2.8740
for 90 % CI value of t = 1.860
margin of error E=t*std error   = 5.344
lower confidence bound=xo-E = 30.42
Upper confidence bound=xo+E= 41.10

c)

t=r*(√(n-2)/(1-r2))= 2.647
critical t = 1.860

d)

l)

std error of slope =se(β1) =s/√Sxx= 0.2912
for 90 % CI value of t = 1.860
margin of error E=t*std error   = 0.542
lower confidence bound=xo-E = 0.229
Upper confidence bound=xo+E= 1.312

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