An 80 kg man stands in a very strong wind moving at 15 m/s at torso...

An 80 kg man stands in a very strong wind moving at 15 m/s at torso height. As you know, he will need to lean in to the wind, and we can model the situation to see why. Assume that the man has a mass of 80 kg, with a center of gravity 1.0 m above the ground. The action of the wind on his torso, which we approximate as a cylinder 50 cm wide and 90 cm long centered 1.2 m above the ground, produces a force that tries to tip him over backward. To keep from falling over, he must lean forward.

Part A

What is the magnitude of the torque provided by the wind force? Take the pivot point at his feet. Assume that he is standing vertically. Assume that the air is at standard temperature and pressure.

Express your answer with the appropriate units.

For Part A. I tried 72.9 degrees, 85.02 degrees and 234.44 (I'm desperate)

Part B

At what angle to the vertical must the man lean to provide a gravitational torque that is equal to this torque due to the wind force?

Express your answer in degrees.

For part B. I already tried 5.25 degrees, 5.5 degrees and 6.5 degrees

I need help please!!!!

Expert Solution

genius_generous answered 8 months ago

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