In: Statistics and Probability
A random sample of the ACT scores of 300 students at Big State
University provided a sample mean score of 21.8 with a sample
standard deviation of 5.632. Find the 95% confidence interval for
the mean score of all Big State students who had taken the
ACT.?
(a) (21.2, 22.4) (b) (21.0, 22.6) (c) (20.9, 22.7) (d) (20.3, 23.3)
(e) (21.3, 22.3)
Solution :
Given that,
= 21.8
s = 5.632
n = 300
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Margin of error = E = Z/2* ( /n)
= 1.96 * ( 5.632/ 300)
= 0.64
At 95% confidence interval estimate of the population mean is,
- E < < + E
21.8 - 0.64 < < 21.8 = 0.64
21.2< < 22.4
(21.2,22.4 )
correct answer is (a)