In: Statistics and Probability
What Do People Do on Facebook?
In a survey of 2255 US adults, we learn that 970 of the respondents
use the social networking site Facebook.1 Of the 970
Facebook users, the survey shows that on an average day:
• 15% update their status
• 22% comment on another’s post or status
• 20% comment on another user’s photo
• 26% ‘‘like” another user’s content
• 10% send another user a private message.
1Hampton, K., Goulet, L., Rainie, L., and Purcell, K.,
‘‘Social Networking Sites and Our Lives,” Pew Research Center, June
16, 2011.
New attempt is in progress. Some of the new entries may impact the last attempt grading.Your answer is partially correct.
(a) For each of the bulleted activities, find a 90% confidence
interval for the proportion of Facebook users engaging in that
activity on an average day.
Round your answers to three decimal places.
Bulleted Activities | Confidence Interval | |||
Update status: | Enter your answer in accordance to item (a) of the question statement | to | Enter your answer in accordance to item (a) of the question statement | |
Comment on another’s post or status: | Enter your answer in accordance to item (a) of the question statement | to | Enter your answer in accordance to item (a) of the question statement | |
Comment on another user’s photo: | Enter your answer in accordance to item (a) of the question statement | to | Enter your answer in accordance to item (a) of the question statement | |
‘‘Like” another user’s content: | Enter your answer in accordance to item (a) of the question statement | to | Enter your answer in accordance to item (a) of the question statement | |
Send another user a private message: | Enter your answer in accordance to item (a) of the question statement | to | Enter your answer in accordance to item (a) of the question statement |
Level of Confidence = 95%
? = 100% - (Level of Confidence) = 5%
?/2 = 2.5% = 0.025
Calculate z?/2 by using standard normal distribution
(normal population with mean (?) = 0 and standard deviation (?) =
1)
with ?/2 = 0.025 as right-tailed area and left-tailed area.
z?/2 = 1.96 (Refer z distribution table)
People who update status (p? =0.15)
Lower Bound = p? - z?/2*?p?(1 - p?)/n = 0.15 -
(1.96)*?[0.15(1 - 0.15)/970] = 0.15 - 1.96*0.0115 = 0.1275
Upper Bound = p? + z?/2*?p?(1 - p?)/n = 0.15 +
(1.96)*(0.0115) = 0.1725
Confidence Interval = (0.1275, 0.1725)
Comment on another's post or status (p? =0.22)
Lower Bound = p? - z?/2•?p?(1 - p?)/n = 0.22 -
(1.96)(0.0133) = 0.1939
Upper Bound = p? + z?/2•?p?(1 - p?)/n = 0.22 +
(1.96)(0.0133) = 0.2461
Confidence Interval = (0.1939, 0.2460)
Comment on another user's photo (p? =0.20)
Lower Bound = p? - z?/2•?p?(1 - p?)/n = 0.2 -
(1.96)(0.01284) = 0.1748
Upper Bound = p? + z?/2•?p?(1 - p?)/n = 0.2 +
(1.96)(0.012843225981358711) = 0.2252
Confidence Interval = (0.1748, 0.2252)
Like another
user's conent (p? =0.26)
Lower Bound = p? - z?/2•?p?(1 - p?)/n = 0.26 -
(1.96)(0.01408) = 0.2324
Upper Bound = p? + z?/2•?p?(1 - p?)/n = 0.26 +
(1.96)(0.01408) = 0.2876
Confidence Interval = (0.2324, 0.2876)
Send another user a private message (p? =0.10)
Lower Bound = p? - z?/2•?p?(1 - p?)/n = 0.1 -
(1.96)(0.0096) = 0.0811
Upper Bound = p? + z?/2•?p?(1 - p?)/n = 0.1 +
(1.96)(0.0096) = 0.1189
Confidence Interval = (0.0811, 0.1189)