A ball is placed at the top of a hill and then released. After 5 seconds...

A ball is placed at the top of a hill and then released. After 5 seconds it has a speed of 20 m/s. What is the average acceleration of the ball? A) 10 m/s^2 B) 0 m/s^2 C) 100 m D)5 m/s^2 E) 4 m/s^2

Expert Solution

When the ball is released from the top of the hill then it's initial velocity (u)=0

And it's final velocity will be after 5 second (v)=20 m/s

Now to calculate the acceleration we need to use Newton's first law os motion:

v=u + at

20 m/s=0 + a×(5second)

a=(20/5) m/s²

a= 4 m/s² (Ans)

So the option (E) is correct.

genius_generous answered 8 months ago

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