Balance the following reaction Zn^+2 + Ba ------> Ba^+2 + Zn

Expert Solution

Zn^+2 + Ba ------> Ba^+2 + Zn

oxidation half reaction reduction half reaction

Ba(s) -------------------> Ba^2+ (aq) + 2e^- Zn^2+ (aq) + 2e^- --------------> Zn(s)

addition of two half reaction

Ba(s) -------------------> Ba^2+ (aq) + 2e^-

Zn^2+ (aq) + 2e^- --------------> Zn(s)

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Ba(s) + Zn^2+ (aq) ------------------> Ba^2+ (aq) + Zn(s)

queen_honey_blossom answered 2 years ago

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