Question

In: Computer Science

#include<stdio.h> #include<stdlib.h> int main() { //Q1) Note: You can use only pointer based operations while...

#include<stdio.h>
#include<stdlib.h>

int main()
{
    //Q1) Note: You can use only pointer based operations while implementing each of the functionalities below
   // zero points will be given if pointer operations are not used in implementing
   // each of the operations below.
   // Also, use C code only in visual studio or GCC in general.asu.edu server

   /* i.) Create a 2 - D array of integers using pointers (use dynamic memory allocation).
           Assume that the array has 4 rows and 5 columns.Then,
           fill the array with randomly generated int values between 1 and 100. */

/* ii.) Find the largest values in the array */

   /*
   iii.) Find the smallest value in the 1st row

   */

   /*
   iv.) Find the smallest value in the 1st column
   */

/*v.) Display the elements in the diagonal
*/

return 0;

C language and please comment on your code

Solutions

Expert Solution

Code

#include <stdio.h>

#include<stdlib.h>

int main(void) {

int r = 4, c = 5;

int i,j,num;

//dynamiclly assing memeory to 2d array

int *arr = (int *)malloc(r * c * sizeof(int));

int min,max;

//add value to the array

for (i = 0; i < r; i++)

for (j = 0; j < c; j++)

{

*(arr + i*c + j) = rand()%(100-1) + 1;

}

max=*(arr + 0*c + 0);

//print array

for (i = 0; i < r; i++)

{

for (j = 0; j < c; j++)

{

printf("%d\t",*(arr + i*c + j));

if(*(arr + i*c + j)>min)

max=*(arr + i*c + j);

}

printf("\n");

}

printf("\nThe largest value in the 1st row: %d\n",max);

//finding min from 1st row

min=*(arr + 0*c + 0);

i=0;

for (j = 0; j < c; j++)

{

if(*(arr + i*c + j)<min)

min=*(arr + i*c + j);

}

printf("\nThe smallest value in the 1st row: %d\n",min);

//finding min from 1st col

min=*(arr + 0*c + 0);

i=0;

for (j = 0; j < r; j++)

{

if(*(arr + i + j*c)<min)

min=*(arr + i + j*c);

}

printf("\nThe smallest value in the 1st col: %d",min);

//prints diagonal elements

printf("\n\nDiagonal Elemnts: ");

for (i = 0; i < r; i++)

for (j = 0; j < c; j++)

if(i==j)

printf("%d\t",*(arr + i*c + j));

return 0;

}

output

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venereology answered 1 month ago

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