Question

In: Computer Science

#include<stdio.h> #include<stdlib.h> int main() {     //Q1) Note: You can use only pointer based operations while...

#include<stdio.h>
#include<stdlib.h>

int main()
{
    //Q1) Note: You can use only pointer based operations while implementing each of the functionalities below
   // zero points will be given if pointer operations are not used in implementing
   // each of the operations below.
   // Also, use C code only in visual studio or GCC in general.asu.edu server


   /* i.) Create a 2 - D array of integers using pointers (use dynamic memory allocation).
           Assume that the array has 4 rows and 5 columns.Then,
           fill the array with randomly generated int values between 1 and 100. */

   /* ii.) Find the largest values in the array */

   /*
   iii.) Find the smallest value in the 1st row
  
   */


   /*
   iv.) Find the smallest value in the 1st column
   */

   /*v.) Display the elements in the diagonal
   */


   return 0;

C language and please comment on your code

Solutions

Expert Solution

Code

#include <stdio.h>

#include<stdlib.h>

int main(void) {

int r = 4, c = 5;

int i,j,num;

//dynamiclly assing memeory to 2d array

int *arr = (int *)malloc(r * c * sizeof(int));

int min,max;

//add value to the array

for (i = 0; i < r; i++)

for (j = 0; j < c; j++)

{

*(arr + i*c + j) = rand()%(100-1) + 1;

}

max=*(arr + 0*c + 0);

//print array

for (i = 0; i < r; i++)

{

for (j = 0; j < c; j++)

{

printf("%d\t",*(arr + i*c + j));

if(*(arr + i*c + j)>min)

max=*(arr + i*c + j);

}

printf("\n");

}

printf("\nThe largest value in the 1st row: %d\n",max);

//finding min from 1st row

min=*(arr + 0*c + 0);

i=0;

for (j = 0; j < c; j++)

{

if(*(arr + i*c + j)<min)

min=*(arr + i*c + j);

}

printf("\nThe smallest value in the 1st row: %d\n",min);

//finding min from 1st col

min=*(arr + 0*c + 0);

i=0;

for (j = 0; j < r; j++)

{

if(*(arr + i + j*c)<min)

min=*(arr + i + j*c);

}

printf("\nThe smallest value in the 1st col: %d",min);

//prints diagonal elements

printf("\n\nDiagonal Elemnts: ");

for (i = 0; i < r; i++)

for (j = 0; j < c; j++)

if(i==j)

printf("%d\t",*(arr + i*c + j));

return 0;

}

output

If you have any query regarding the code please ask me in the comment i am here for help you. Please do not direct thumbs down just ask if you have any query. And if you like my work then please appreciates with up vote. Thank You.

venereology answered 9 months ago
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