Question

Complete parts​ (a) and​ (b) below.

The number of dogs per household in a small town

(a) Find the​ mean, variance, and standard deviation of the probability distribution.

Find the mean of the probability distribution.

u=___(Round to one decimal place if needed)

Find the variance of the probability distribution.

o2=___(round to one decimal place if needed)

find the standard deviation of the probability distribution

o=____(round to one decimal place when needed)

(b) Interpret the results in the context of the​ real-life situation.

A) a household on average has 0.5 dogs with a standard deviation of 0.9 dogs

B. A household on average has

0.5

dog with a standard deviation of

eleven

dogs.

C. A household on average has

0.9

dog with a standard deviation of

0.5

dog.

D.

A household on average has

0.8

dog with a standard deviation of

0.9

dog.

.9

Answer 1

The number of dogs per household in a small town values are not given so we can assume the values for need of calculation

(a) The mean of the probability distribution:

we know that,

mean= μ = Σxp = 0 + 0.241 + 0.18 + 0.069 + 0.056 + 0.045 = 0.591

The variance of the probability distribution:

variance=Var(X) = Σx²p − μ²

                            = 0 + 0.241 + 0.36 + 0.207 + 0.224 + 0.225 = 1.257 - (0.591)²

                            = 1.257 - (0.591)²

variance=Var(X) = 0.907719 or 0.9

The standard deviation of the probability distribution :

The Standard Deviation is the square root of the Variance:

σ = √Var(X)

σ = √0.9 = 0.94868 or 0.9

(b) a household on average has 0.5 dogs with a standard deviation of 0.9 dogs

option-A is correct