Question

In: Chemistry

Given stock solutions of 25 mM nitrophenyl phosphate, and 1.5 M tris,pH 7.2, 7.5 mM MgCl2....

Given stock solutions of 25 mM nitrophenyl phosphate, and 1.5 M tris,pH 7.2, 7.5 mM MgCl2. If you mix 0.1ml of the nitrophenyl phosphate, 0.7 ml of the tris solution and 0.2 ml of water to bring the total volume to 1 ml, what is the final concentrations of each of the components in the final solution? Show work

Nitrophenyl phosphate in mM

Tris in M

Magnesium chloride in mM

Expert Solution

In the given question, we are adding 0.1ml of the nitrophenyl phosphate, 0.7 ml of the tris solution and 0.2 ml of water to bring the total volume to 1 ml.

Total volume = 1 ml

We need to first calculate the no of mmols in 0.1ml of the nitrophenyl phosphate

Molarities of Stock solutions of nitrophenyl phosphate, tris,pH 7.2 and MgCl₂ will give us the No. of moles of each species in 1 Lt of Volume.

Molarity= No. of moles dissolved in 1 Lt of solution

So, 25 mM nitrophenyl phosphate will contain 25 mmols of nitrophenyl phosphate in 1 Lt of volume.

1 lt (1000 ml) of 25 mM nitrophenyl phosphate solution will contain = 25 mmols of nitrophenyl phosphate

0.1ml of 25 mM nitrophenyl phosphate solution will contain= 0.1 * 25 /1000 = 25* 10^-4 mmoles ofnitrophenyl phosphate

Similarly

1.5 M tris(pH 7.2) will contain 1.5 mols (1500 mmols) of tris in 1 Lt of volume.

0.7 ml of 1.5 M tris(pH 7.2) solution will contain= 0.7* 1.5 /1000 = 1.05* 10^-3 moles oftris

So we are adding 25* 10^-4 moles ofnitrophenyl phosphate and 1.05* 10^-3 mols oftris and making the total volume 1 ml by diluting with water.

Now we will calculate the molarity,

For nitrophenyl phosphate :

1 ml of total volume contains = 25* 10^-4 mmoles ofnitrophenyl phosphate

1000 ml of total volume will contain = 25* 10^-1mmoles ofnitrophenyl phosphate or 2.5 mmols

Concentration of nitrophenyl phosphate = 2.5 mmoles/Lt = 2.5mM

For Tris:

1 ml of total volume contains = 1.05* 10^-3 moles oftris

1000 ml of total volume will contain = 1.05 moles oftris

Concentration of tris = 1.05 moles/Lt = 1.05 M

Since we have not added MgCl2 in given question, its Concentration will be zero.

queen_honey_blossom answered 2 years ago

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