Question

 

a) Assuming this right skewed population distribution had a population mean of 14.05 and a standard deviation of 11.83; calculate the probability that, in a random sample of 30, the mean of the sample is greater than 16. First, draw a picture with the mean labeled, shade the area representing the desired probability, standardize, and use the Standard Normal Table (Table 2 in your text) to obtain this probability. Please take a picture of your hand drawn sketch and upload it to your Word document (if you do not have this technology, you may use any other method (i.e. Microsoft paint) to sketch the image). You must type the rest of your “by hand” work to earn full credit.

Answer 1

µ = 14.05

sd = 11.83

n = 30

                         

                          = P(Z > 0.90)

                          = 1 - P(Z < 0.9)

                          = 1 - 0.8159

                          = 0.1841