Question

C++

A void function named NextLeapYear() that takes an int reference parameter. If the parameter is positive, the function will assign it the next leap year after it; otherwise, the function will assign 4 to it.

Answer 1

The C++ code sniffet of main.cpp is:

#include <iostream>

void NextLeapYear(int *year)
{
    int temp = *year; //to prevent any mid changes in variable.
    if(temp < 0) //negative entry check
    {
        *year = 4;
        return;
    }
    temp = ((temp/4)+1)*4; // this is most probable leap yr next to year provided.
    //Nested if statements check if temp contains a year which is multiple of 100 and not a multiple of 400 like 1900 which is not a leap year.
    if(temp%100 == 0)
    {
        if(temp%400 != 0)
        {
            temp += 4;
        }
    }
    *year = temp;
    return;
}

int main() {
    int yr;
    std::cout << "Hello world!\n";
    std::cout << "Enter a year: ";
    std::cin >> yr;
    NextLeapYear(&yr);
    std::cout << "Next Leap Year is: " << yr;

    return 0;
}

The function NextLeapYear() is:

void NextLeapYear(int *year)
{
    int temp = *year; //to prevent any mid changes in variable.
    if(temp < 0) //negative entry check
    {
        *year = 4;
        return;
    }
    temp = ((temp/4)+1)*4; // this is most probable leap yr next to year provided.
    //Nested if statements check if temp contains a year which is multiple of 100 and not a multiple of 400 like 1900 which is not a leap year.
    if(temp%100 == 0)
    {
        if(temp%400 != 0)
        {
            temp += 4;
        }
    }
    *year = temp;
    return;
}

Sample Output:

Hope it helps.