(Discrete Math) Prove that the equation 2x² + y² = 14 has no positive integer solutions.

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Colby Messinger answered 2 years ago

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You can verify that the differential equation: −7x2y′′−14x(x−1)y′+14(x−1)y=0−7x2y″−14x(x−1)y′+14(x−1)y=0, x>0x>0 has solutions y1=3xy1=3x and y2=5xexp(−2x)y2=5xexp⁡(−2x). Compute the...

You can verify that the differential equation: −7x2y′′−14x(x−1)y′+14(x−1)y=0−7x2y″−14x(x−1)y′+14(x−1)y=0, x>0x>0 has solutions y1=3xy1=3x and y2=5xexp(−2x)y2=5xexp⁡(−2x). Compute the Wronskian WW between y1y1 and y The solutions y1y1 and y2y2 form a fundamental set of solutions because there is a point x0x0 where W(x0)≠0W(x0)≠0

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(Discrete Math) Prove that the equation 2x² + y² = 14 has no positive integer solutions.

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You can verify that the differential equation: −7x2y′′−14x(x−1)y′+14(x−1)y=0−7x2y″−14x(x−1)y′+14(x−1)y=0, x>0x>0 has solutions y1=3xy1=3x and y2=5xexp(−2x)y2=5xexp⁡(−2x). Compute the...

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