In: Statistics and Probability
Population 1 has an estimated mean of 50 and a sample standard deviation of 3 while population 2 has a sample mean of 48 and a sample standard deviation of 4. A sample of size 16 is taken for each population. |
With the null being equality of means and the alternative being that the means are not equal, the conclusion as to the equality of means at the 90% level of confidence would be: |
A. Accept the null of no difference. |
B. Reject the null of no difference. |
With the null being equality of means and the alternative being that the mean of population 1 exceeds the mean of population 2, the critical value of t would be? |
With the null being equality of means and the alternative being that the mean of population 1 exceeds the mean of population 2, the conclusion as to the equality of means at the 90% level of confidence would be: |
A. Accept the null of no difference. |
B. Reject the null of no difference. |
With the null being equality of means and the alternative being that the means are not equal, the conclusion as to the equality of means
i.e Two tailed test :
Given | |
n1 : Sample Size of sample 1 | 16 |
n2 : Sample Size of Sample 2 | 16 |
: Sample Mean of Sample 1 | 50 |
: Sample Mean of Sample 2 | 48 |
s1: Sample Standard Deviation of sample 1 | 3 |
s2 : Sample Standard Deviation of Sample 2 | 4 |
Confidence level | 90% |
Level of Significance : (100-90)100 | 0.10 |
For Two tailed test :
for degrees of freedom : 27 ; P(t>1.6) = 0.0606
As P-Value i.e. is greater than Level of significance i.e (P-value:0.1212 > 0.1:Level of significance); Fail to Reject Null Hypothesis
Ans :
A. Accept the null of no difference.
With the null being equality of means and the alternative being that the mean of population 1 exceeds the mean of population 2
i.e. Right tailed test :
For Right Tailed test :
As P-Value i.e. is less than Level of significance i.e (P-value:0.0606 < 0.1:Level of significance); Reject Null Hypothesis
Ans :
B. Reject the null of no difference.