In: Statistics and Probability
A web-based company has a goal of processing 95 percent of its orders on the same day they are received. If 495 out of the next 514 orders are processed on the same day, would this prove that they are exceeding their goal, using α = .025? |
(a) |
H0: ππ ≤ .95 versus H1: ππ > .95. Choose the right option. |
a. | Reject H0 if zcalc > 1.96 |
b. | Reject H0 if zcalc < 1.96 |
|
(b) |
Calculate the test statistic. (Round your answer to 3 decimal places.) |
Test statistic |
(c-1) | The null hypothesis should be rejected. |
|
(c-2) | The true proportion is greater than .95. |
|
(c-3) | The company is exceeding its goal. |
|
Solution:
One proportion z test
Hypothesis are
H0: π ≤ .95 versus H1: π > .95
> sign in H1 indicates that right tailed test.
n= 514
x = 495
α = .025
Let denotes the sample proportion.
= x/n = 495 / 514 = 0.963
a) Critical region
For right tailed test , the critical region is >
α = 0.025 and 1 - α = 0.975
= 1.96 ..use z table
Critical region is : Reject H0 if zcalc > 1.96
b)The test statistic z is
zcalc = where p = π = 0.95
= (0.963 - 0.95) / (0.95*0.05 / 514)
= 1.356
c 1) zcalc = 1.356 is less than = 1.96
So , The null hypothesis should not be rejected
Answer is NO
c2 ) The true proportion is greater than .95.
No evidence to support
c3) The company is exceeding its goal.
No evidence to support