In: Statistics and Probability
Win/Loss and With/Without Joe: Joe plays basketball for the Wildcats and missed some of the season due to an injury. The win/loss record with and without Joe is summarized in the contingency table below.
Observed Frequencies: Oi's
Wins | Losses | Totals | |
With Joe | 15 | 7 | 22 |
Without Joe | 6 | 12 | 18 |
Totals | 21 | 19 | 40 |
The Test: Test for a significant dependent relationship between the outcome of the game (win/lose) and whether or not Joe played. Conduct this test at the 0.05 significance level.
(a) What is the null hypothesis for this test?
H0: The outcome of the game and whether or not Joe plays are dependent variables.
H0: The outcome of the game and whether or not Joe plays are independent variables.
H0: The probability of winning is dependent upon whether or not Joe plays.
(b) What is the value of the test statistic? Round to 3
decimal places unless your software automatically rounds to 2
decimal places.
Ļ2 =
(c) USE SOFTWARE to get the P-value of the test
statistic. Round to 4 decimal places unless your software
automatically rounds to 3 decimal places.
P-value =
(d) What is the conclusion regarding the null hypothesis?
reject H0
fail to reject H0
(e) Choose the appropriate concluding statement.
We have proven that Joe causes the team to do better.
The evidence suggests that the outcome of the game is dependent upon whether or not Joe played.
There is not enough evidence to conclude that the outcome of the game is dependent upon whether or not Joe played.
We have proven that the outcome of the game is independent of whether or not Joe played.
( a ) the null hypothesis for this test is
H0: The outcome of the game and whether or not Joe plays are independent variables.
( b ) The value of the test statistic is
( c ) P-value of the test statistic :
with chi square = 4.821 ,df = 1
P-value = 0.02811503
~ 0.0281
( d ) conclusion :
p value < l.o.s
0.0281 < 0.05
reject H0
( e )
The evidence suggests that the outcome of the game is dependent upon whether or not Joe played.
0.02811503 |