Question

In: Physics

2 chainz

2 chainz

Solutions

Expert Solution

2)


initial veloity = vi = 0


final velocity = vf = 29.8 m/s

time taken t= 5 s

aceeleration = rate of change in accelaration


a = (vf-vi)/t


a = (29.8-0)/5 = 5.96 m/s^2


from newtons lwa F = m*a

F = 2087*5.96 = 12438.52 N    <-----------answer


+++++++++++++++++++


3)

W = F.S = F*S*costheta = F*costheta*S


here F*costheta = horizantal componrent = 42.5 N


W = 42.5*82.8 = 3519 J       <-----------answer

======================


4)

spring constant = k = F/dx = mg/dx


K = (79.3*9.8)/0.31


K = 2506.9 N/m   <-----------answer

+++++++++++++++++++++


5)


spring constant = k = F/dx = mg/dx


K = (84.8*9.8)/0.29


K = 2865.66 N/m


time period T = 2*pi*sqrt(m/K)


T = 2*3.14*sqrt(2865.66/84.8) = 36.5 s   <-----------answer

=======================

6)

spring constant = k = F/dx = mg/dx


K = (96.1*9.8)/0.2


K = 4708.9 N/m


U = 0.5*k*x^2 = 0.5*4708.9*0.2*0.2 = 94.178 J    <-----------answer


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