In: Math
We must show our work.
1. A sample of 81 observations is taken from a normal population with a standard deviation of 5. The sample mean is 40. Determine the 80% confidence interval for the population mean. (Hint: Confidence Interval for a Population mean with population standard deviation (σ) known)
Solution :
Given that,
= 40
= 5
n = 81
At 80% confidence level the z is ,
= 1 - 80% = 1 - 0.80 = 0.20
/ 2 = 0.20 / 2 = 0.10
Z/2 = Z0.10 = 1.28
Margin of error = E = Z/2* ( /n)
= 1.28 * (5 / 81)
= 0.71
At 80% confidence interval estimate of the population mean is,
- E < < + E
40 - 0.71 < < 40 + 0.71
39.29 < < 40.71
(39.29, 40.71)