Derive an expression for the instantaneous voltage across the capacitor. Express your answer in terms of the variables C, R, I0, and t.
My previous answers that were incorrect: 1) VC=I0*Cos(omega*t)*R (Response was that the answer doesn't depend on (omega*t) 2)Vc=I0*Cos((1/RC)*t)*R (Response was Incorrect; Try Again; One attempt remaining You have found the voltage across the resistor. Note that the current and voltage across the capacitor are out of phase.)
Previous question info:
Part A) A 300 Ω resistor is connected in series with a 50 mH inductor. The voltage across the resistor is vR=(1.20V)cos(2500rad/s)t. Find the amplitude of the voltage across the inductor.
Part B) What should multiply the amplitude to obtain an expression for the instantaneous voltage vL across the inductor?
Part C) The current through a series combination of a capacitor C and resistor R is given by I0cos(ωt), where ω is chosen so that the reactance of the capacitor is equal to the resistance R. Derive an expression for ω.
Thank you
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A dielectric-filled parallel-plate capacitor has plate area AAA = 20.0 cm2cm2 , plate separation ddd = 5.00 mmmm and dielectric constant kkK = 5.00. The capacitor is connected to a battery that creates a constant voltage VVV = 12.5 VV . Throughout the problem, use ϵ0ϵ0epsilon_0 = 8.85×10−12 C2/N⋅m2C2/N⋅m2 . |
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